y^2-2y-2.5=0

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Solution for y^2-2y-2.5=0 equation: 



y^2-2y-2.5=0

a = 1; b = -2; c = -2.5;
Δ = b2-4ac
Δ = -22-4·1·(-2.5)
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{14}}{2*1}=\frac{2-\sqrt{14}}{2}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{14}}{2*1}=\frac{2+\sqrt{14}}{2}
$

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